x^2-6x-6+x*根號下x^2-2x-2=0

熱心網友

x^2-6x-6+x*(x^2-2x-2)^0.5=0x^2-6x-6=-x*(x^2-2x-2)^0.5(x^2-6x-6)^2=[-x*(x^2-2x-2)^0.5]^2x^4+36x^2+36-12x^3-12x^2+72x=x^4-2x^3-2x^2-5x^3+13x^2+36x+18=0(x+1)(-5x^2+18x+18)=0x1=-1,x2,3=(9±171^0.5)/5經檢驗,

熱心網友

共有兩個實根：x1=-1,x2=9/5+(3√19)/5。