f(x)=loga^x(a>0,a≠1),已知f(25)=2,則f-1(log25^2)=
熱心網友
由f(25)=2可得a=5f-1(log25^2)=?即函數當X=?時f(x)=log25^2又log25^2=1/2*log5^2=log5^根號(2)所以f-1(log25^2)=根號(2)
f(x)=loga^x(a>0,a≠1),已知f(25)=2,則f-1(log25^2)=
由f(25)=2可得a=5f-1(log25^2)=?即函數當X=?時f(x)=log25^2又log25^2=1/2*log5^2=log5^根號(2)所以f-1(log25^2)=根號(2)