已知XYZ互不等,X+Y+Z=1求證(1/X-1)(1/Y-1)(1/Z-1)>8

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還缺條件X,Y,Z是正數(shù),否則如X=-6,Y=3,Z=4,不等式不成立證明:X0,Y0,Z0,X+Y+Z=1,X,Y,Z互不相等(1/X-1)(1/Y-1)(1/Z-1)=[(X+Y+Z)/X-1][(X+Y+Z)/Y-1][(X+Y+Z)/Z-1]=(Y+Z)(X+Z)(X+Y)/(XYZ)2√(YZ)*2√(XZ)*2√(XY)/(XYZ)=8