設(shè)0<a<1/2,0<b<1/2,則lgalgb與lg^2(a+b)的大小關(guān)系是_________.請寫出分析過程.
0 1 a+b a 0, 1 a+b b 0== 0 lg(a+b) lga, 0 lg(a+b) lgb== 0 [-lg(a+b)]*[-lg(a+b)] lg(a+b)*lg(a+b) = [lg(a+b)]^2 < lga*lgb
