x^2 + 1 = x + 6/x(x-1)
移項得：x(x-1）+1-6/x(x-1）=0，令x(x-1）=t,則t^+t-6=0(^表示平方）解得：t=-3或2，當t=-3時：x^-x+3=0無解，當t=2時：x^-x-2=0,所以x=2或-1
