奇函數(shù)f(x)滿足f(x+2)=f(x),若f(x)在區(qū)間(-3,-2)上遞減且f(x)>0則A.f(-2/3)<f(-1/2)B.f(-2/3)>f(-1/2)C.f(-2/3)=f(-1/2)D.f(-2/3)與f(-1/2)的大小關(guān)系要視對(duì)應(yīng)規(guī)律f而定請(qǐng)簡(jiǎn)要寫(xiě)出解答過(guò)程,謝謝!

熱心網(wǎng)友

因?yàn)閒(x)=f(x+2),將x換成t-2,所以f(t-2)=f(t),即f(x-2)=f(x)所以f(-2/3)=f(-2/3-2)=f(-8/3),f(-1/2)=f(-1/2-2)=f(-5/2),而-5/2-8/3,而函數(shù)在(-3,-2)上遞減,所以f(-5/2)f(-1/2)