計算題：[（X的平方+7X+10）/X的平方-X+1]乘以[（X的立方+1）/（X的平方+4X+4）]/[（X+1）/（X+2）]

熱心網友

解：原式=[(x+2)(x+5)]/(x^2-x+1)×[(x+1)(x^2-x+1)/(x+2)^2]×(x+2)/(x+1)=x+5.

熱心網友

原式＝[（ｘ+2）（ｘ+5）/（ｘ^2-x+1)*(x+1)(x^2-x+1)/(x+2)^2]/[（X+1）/（X+2）] =[(x+5)(x+1)/(x+2)]/[（X+1）/（X+2）] ==(x+5)(x+1)(x+2)/（X+1)(x+2)=x+5