請分析并解答，謝謝~~
熱心網(wǎng)友
根據(jù)題意有：U1=U2 == I1R1=I2R2 ==I2=I1R1/R2=2R1/2=R1I1+I2=I3, U=U1+U3=U2+U3 ==U=I1R1+P3/(I1+I2)=2R1+15/(2+R1)=9所以 ==(R1-3)(2R1+1)=0 ==R1=3Ω(舍負(fù))所以 ==U3=U-U1=9-6=3V ==R3=U3^2/P3=9/15=3/5Ω
熱心網(wǎng)友
R3=3/5歐姆R1=5/2歐姆
請分析并解答，謝謝~~
根據(jù)題意有：U1=U2 == I1R1=I2R2 ==I2=I1R1/R2=2R1/2=R1I1+I2=I3, U=U1+U3=U2+U3 ==U=I1R1+P3/(I1+I2)=2R1+15/(2+R1)=9所以 ==(R1-3)(2R1+1)=0 ==R1=3Ω(舍負(fù))所以 ==U3=U-U1=9-6=3V ==R3=U3^2/P3=9/15=3/5Ω
R3=3/5歐姆R1=5/2歐姆