f(x)的反函數是f-1(x),則函數f(2x-1)+1反函數是_____
熱心網友
f(x)的反函數是f~(x),則函數f(2x-1)+1反函數是?由反函數定義，f(x)=y,則f~(y)=x將上式中x，y分別以(2x-1)、(y-1)代入，有：f(2x-1)=y-1,f~(y-1)=2x-1即：y=f(2x-1)+1則：2x-1=f~(y-1)x=[f~(y-1)+1]/2將x、y符號兌換：y=[f~(x-1)+1]/2∴f(2x-1)+1反函數是[f~(x-1)+1]/2
f(x)的反函數是f-1(x),則函數f(2x-1)+1反函數是_____
f(x)的反函數是f~(x),則函數f(2x-1)+1反函數是?由反函數定義，f(x)=y,則f~(y)=x將上式中x，y分別以(2x-1)、(y-1)代入，有：f(2x-1)=y-1,f~(y-1)=2x-1即：y=f(2x-1)+1則：2x-1=f~(y-1)x=[f~(y-1)+1]/2將x、y符號兌換：y=[f~(x-1)+1]/2∴f(2x-1)+1反函數是[f~(x-1)+1]/2