還是求導(dǎo)y=ln(x+跟號(hào)x^2+a^2)

熱心網(wǎng)友

y=ln[x+√(x^2+a^2)]y'={1/[x+√(x^2+a^2)]}[x+√(x^2+a^2)]' ={1/[x+√(x^2+a^2)]}{1+(1/2)[1/√(x^2+a^2)](x^2+a^2)'} ={1/[x+√(x^2+a^2)]}{1+[x/√(x^2+a^2)]} =1/√(x^2+a^2)