某石灰石樣品12.25g（雜質(zhì)不溶于水，也不與酸反應(yīng)）恰好與94.4g稀鹽酸完全反應(yīng)，生成4.4g二氧化碳，計(jì)算（1）原樣品中碳酸鈣的質(zhì)量分?jǐn)?shù)（2）反應(yīng)后所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)

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某石灰石樣品12.25g（雜質(zhì)不溶于水，也不與酸反應(yīng)）恰好與94.4g稀鹽酸完全反應(yīng)，生成4.4g二氧化碳，計(jì)算（1）原樣品中碳酸鈣的質(zhì)量分?jǐn)?shù)（2）反應(yīng)后所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)解：CaCO3+2HCl=CO2+CaCl2+H2O100 44 111x 4.4g yx=10g y=11.1gCaCO3的質(zhì)量分?jǐn)?shù)是10/12.25=81.6%,雜質(zhì)為12.25-10=2.25g恰好完全反應(yīng)，溶質(zhì)是CaCl2,11.1g.溶液總質(zhì)量為12.25+94.4-2.25-4.4=100g11.1/100=11.1%反應(yīng)后所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)11.1%

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CaCO3---CO2----CaCl 1x4.4gyx=10gy=11.1gCaCO3的質(zhì)量分?jǐn)?shù)是10/12.25=81.6%,雜質(zhì)為12.25-10=2.25g恰好完全反應(yīng),溶質(zhì)是CaCl2,11.1g.溶液總質(zhì)量為12.25+94.4-2.25-4.4=100g11.1/100=11.1%反應(yīng)后所得溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)11.1%