已知:數(shù)列{an},a1=3,sn+1+sn=2an+1.求通項(xiàng)公式an.解:Sn+1=sn+an+1,sn+1+sn=2an+1所以 an+1=2sn,sn=an+1/2an=sn-sn-1=an+1/2-an/2an+1=3an.(n>=2),an=

熱心網(wǎng)友

已知:數(shù)列{An},A1=3,Sn+1+Sn=2An+1.求通項(xiàng)公式An.解:Sn+1=Sn+An+1,Sn+1+Sn=2An+1所以 An+1=2Sn,A1=3,A2=2A1,S2=3A1A3=2*3A1,S3=3*3A1=3^2A1=3^3,Sn-1=3^(n-1)An=2*3^(n-1)你的推導(dǎo)沒錯(cuò),an+1=3an.(n=2),但你沒繼續(xù)討論N=1即A2=2A1=2*3,功虧一簣!

熱心網(wǎng)友

不會(huì)用大小寫啊,看的我好累啊

熱心網(wǎng)友

你這題沒說是什么一數(shù)列,你這樣是按等差來做的,當(dāng)然是錯(cuò)的.........你看清楚題目啊.....................