熱心網(wǎng)友
|x+3|+(y-1)^2=0,而|x+3|≥0,(y-1)^2≥0,所以只能|x+3|=0且(y-1)^2=0所以x=-3,y=1,所以[-4/(y-x)]=-1:當(dāng)n為偶數(shù)時:[-4/(y-x)]的n次方=1:當(dāng)n為奇數(shù)時:[-4/(y-x)]的n次方=-1
|x+3|+(y-1)^2=0,而|x+3|≥0,(y-1)^2≥0,所以只能|x+3|=0且(y-1)^2=0所以x=-3,y=1,所以[-4/(y-x)]=-1:當(dāng)n為偶數(shù)時:[-4/(y-x)]的n次方=1:當(dāng)n為奇數(shù)時:[-4/(y-x)]的n次方=-1